我需要用“FF432423FA112”之類的字串中的數字替換多個文字。“A”=0，“B”=1 等。我嘗試過像這樣回圈，但它沒有用。也嘗試使用 char 陣列
String test = "FF432423FA112";
String[] letters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
for (int i=0; i<letters.length; i ) {
newStr = test.replace(letters[i],i);
}
uj5u.com熱心網友回復：
那是因為你忘記使用了newStr.replace，每次回圈都會生成最后一個test.replace復制字符
String test = "FF432423FA112";
String[] letters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
String newStr = test;
for (int i=0; i<letters.length; i ) {
newStr = newStr.replace(letters[i], i "");
}
System.out.println(newStr);
uj5u.com熱心網友回復：
如果給定的字串是“FF432423FA112”并且預期的輸出是“5543242350112”，考慮到只替換字母并保留數字，下面的代碼就是一個例子。
public class Main {
public static void main(String[] args) {
String test = "FF432423FA112";
String letters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
StringBuilder output = new StringBuilder();
int value = 0;
for (int i=0; i<test.length(); i ) {
char c = test.charAt(i);
if(Character.isDigit(c)) {
value = Character.getNumericValue(c);
} else {
value = letters.indexOf(c);
}
output.append(value);
}
System.out.println(output);
}
}
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