Dart-轉換通過HTTPREST-API獲取的物件映射

Map<LocalDate, List<Event>>對于我的日歷，我從后端 (*JAVA-Type = )獲得以下 JSON 資料：

{
    "2022-05-28": [
        {
            "id": 2,
            "title": "Multi day Event",
            "fromDate": "2022-05-27T12:22:03.873569",
            "toDate": "2022-05-28T11:22:03.873569",
            "room": {
                "id": 1,
                "name": "TestRoom",
            },
            "user": {
                "id": 1,
                "name": "Andi",
                "city": "",
                "email": "[email protected]",
            },
            "eventType": "sozial"
        }
    ],
    "2022-05-27": [
        {
            "id": 2,
            "title": "Multi day Event",
            "fromDate": "2022-05-27T12:22:03.873569",
            "toDate": "2022-05-28T11:22:03.873569",
            "room": {
                "id": 1,
                "name": "TestRoom",
            },
            "user":  {
                "id": 1,
                "name": "Andi",
                "city": "",
                "email": "[email protected]",
            },
            "eventType": "sozial"
        },
        {
            "id": 1,
            "title": "Testevent",
            "fromDate": "2022-05-27T11:21:04.573754",
            "toDate": "2022-05-27T12:21:04.573754",
            "room": {
                "id": 1,
                "name": "TestRoom",
            },
            "user":  {
                "id": 1,
                "name": "Andi",
                "city": "",
                "email": "[email protected]",
            },
            "eventType": "normal"
        }
    ],
}

我的事件類看起來像：

Class Event {
    int id;
    String title;
    DateTime fromDate;
    DateTime toDate;
    Room room;
    User user;
    String eventType;
}

現在我需要與我在后端 ( Map<DateTime, <List<Event>>) 中的日歷小部件相同的結構，但我不知道如何做到這一點。如果我得到一個物件串列，我知道如何將 json 資料轉換為一個物件，但是如何將日期存盤為結果映射的鍵？

我現在的代碼：

Future<Map<DateTime, List<Event>>> getEvents(DateTime _fromDate, DateTime 
_endDate) async {
    String _from = _fromDate.toString().split('.').first;
    String _end = _endDate.toString().split('.').first;

    final response = await get('${_url}calendar/events/$_from/$_end',
    headers: {HttpHeaders.authorizationHeader: 'Bearer $_bearer'});
    if (response.status.hasError) {
       return Future.error('${response.statusText}');
    } else {
       final parsed = jsonDecode(response.body);
       return parsed;
    }
}

uj5u.com熱心網友回復：

你需要做這樣的事情：

var json = {...}; // <-- json obj
  
  // method to parse data to map with list Event
  dynamic fromJson(Map<String, dynamic> json){
    var map = new Map();
    json.keys.forEach((key){
      // key is the date
      map[key] = json[key].map((e) => Event.fromJson(e)).toList(); // <- need to create a method fromJson in your Event class
    });
    return map;
  }
  
  (...)

class Event {
    int id;
    String title;
    DateTime fromDate;
    DateTime toDate;
    Room room;
    User user;
    String eventType;
  
  fromJson(Map<String, dynamic> json) => Event(...); // <- parse json to Event class
}

標籤：扑 休息 字典 http 移动的

上一篇：構建程序失敗，沒有正確的應用程式enwindows

下一篇：HTTPCache-Control標頭max-age與max-age，必須重新驗證