是否可以將這種 "2022-11-11T00:00:00" or this "2022-11-11T12:00:00 01:00"以字串形式出現的 Java（可能是 ISO 8601）格式轉換為具有日期或時間類的簡單格式“yyyy-mm-dd”，或者應該使用字串方法來完成？
例子：
you receive this -> "2022-11-11T00:00:00"
you convert to this -> "2022-11-11"
uj5u.com熱心網友回復：
推薦方式：java.time
如果您需要根據這些值計算任何內容，或者可能找出星期幾，最好使用以下方法java.time：
public static void main(String[] args) {
// example input in ISO format
String first = "2022-11-11T00:00:00";
String second = "2022-11-11T12:00:00 01:00";
// parse them to suitable objects
LocalDateTime ldt = LocalDateTime.parse(first);
OffsetDateTime odt = OffsetDateTime.parse(second);
// extract the date from the objects (that may have time of day and offset, too)
LocalDate firstDate = ldt.toLocalDate();
LocalDate secondDate = odt.toLocalDate();
// format them as ISO local date, basically the same format as the input has
String firstToBeForwarded = firstDate.format(DateTimeFormatter.ISO_LOCAL_DATE);
String secondToBeForwarded = secondDate.format(DateTimeFormatter.ISO_LOCAL_DATE);
// print the results (or forward them as desired)
System.out.println(firstToBeForwarded);
System.out.println(secondToBeForwarded);
}
這個例子的輸出是
2022-11-11
2022-11-11
不推薦，但可能：String操縱
如果你只需要
- 提取日期部分（年、年月和月日）和
- 您確定它始終是
String您收到的 s的前 10 個字符
你可以簡單地取前 10 個字符：
String toBeForwarded = "2022-11-11T00:00:00".substring(0, 10);
該行將存盤"2022-11-11"在toBeForwarded.
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