使用pyqt5從.qml檔案中獲取單選按鈕值

如何使用 pyqt5 從 .qml 檔案中獲取單選按鈕值？.qml 檔案如下：

    import QtQuick 2.15
import QtQuick.Controls 2.15

ApplicationWindow {
    visible: true
    width: 600
    height: 500
    title: "HelloApp"

    RadioButton {
     id: button1
     text: "1"
     objectName: "radio_button"
 }
    TextInput {
              id: text_input
              objectName: "Textinput"
              x:300
              y:300
              width: 80
              height: 20
           }
    Button {
                id: button_execute
                x: 158
                y: 341
                width: 211
                height: 36
                text: qsTr("Execute")
                onClicked: {
                         con.on_execute()
                    }
        }
}

讀取這個.qml檔案的python代碼如下：

import sys
from os.path import abspath, dirname, join
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQml import QQmlApplicationEngine
from PyQt5.QtCore import QObject, pyqtSlot


class Bridge(QObject):
    @pyqtSlot()
    def on_execute(self):
        win = engine.rootObjects()[0]
        # This will give me the value of text input
        text_val = win.findChild(QObject, "Textinput").property("text")
        # How to get the radio button value if it's checked or not checked?

app = QGuiApplication(sys.argv)
if __name__ == '__main__':
    # Reading the qml file
    engine = QQmlApplicationEngine()
    context = engine.rootContext()
    bridge = Bridge()
    context.setContextProperty("con", bridge)
    qmlFile = join(dirname(__file__), 'qml_test_1.qml')
    engine.load(abspath(qmlFile))

    if not engine.rootObjects():
        sys.exit(-1)

    sys.exit(app.exec_())

我的問題是如何知道單選按鈕是否被選中。我嘗試使用 objectName。但這不起作用。

uj5u.com熱心網友回復：

不要使用物件名稱，這是不好的做法。使用信號和插槽或模型。

例子：

main.py

import sys
from os.path import abspath, dirname, join
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQml import QQmlApplicationEngine
from PyQt5.QtCore import QObject, pyqtSlot


class App(QObject):
    def __init__(self, parent=None):
        super().__init__(parent)
        self.current_rb_text = ""

    @pyqtSlot(str)
    def set_current_rb_text(self, text: str):
        self.current_rb_text = text

    @pyqtSlot()
    def on_execute(self):
        print(self.current_rb_text)

app = QGuiApplication(sys.argv)
if __name__ == '__main__':
    # Reading the qml file
    engine = QQmlApplicationEngine()
    context = engine.rootContext()
    bridge = App()
    context.setContextProperty("App", bridge)
    qmlFile = join(dirname(__file__), 'main.qml')
    engine.load(abspath(qmlFile))

    if not engine.rootObjects():
        sys.exit(-1)

    sys.exit(app.exec_())

MyRadioButton.qml

import QtQuick 2.15
import QtQuick.Controls 2.15


RadioButton {id:btn
    onClicked:App.set_current_rb_text(btn.text)
}

main.qml

import QtQuick 2.15
import QtQuick.Controls 2.15
import QtQuick.Layouts 1.14

ApplicationWindow {
    visible: true
    width: 600
    height: 500
    title: "HelloApp"


ColumnLayout{
    MyRadioButton {
     id: button1
     text: "1"
     objectName: "radio_button"
 }
     MyRadioButton {
     id: button2
     text: "2"
     objectName: "radio_button"
 }
     MyRadioButton {
     id: button3
     text: "3"
     objectName: "radio_button"
 }
}
    TextInput {
              id: text_input
              objectName: "Textinput"
              x:300
              y:300
              width: 80
              height: 20
           }
    Button {
                id: button_execute
                x: 158
                y: 341
                width: 211
                height: 36
                text: qsTr("Execute")
                onClicked: {
                         App.on_execute()
                    }
        }
}

注意：您使用的是非常舊的 pyqt5，我建議您使用 PySide6.3，因為它是官方的 Qt 系結并且它對 qml 有更好的支持，例如在這里您可以在 python 中宣告一個屬性并將其系結到單選按鈕文本。

標籤：Python qt pyqt5 qml

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