x = [0.0000000,0.0082707,0.0132000, 0.0255597, 0.0503554, 0.0751941, 0.1000570,
0.1498328, 0.1996558, 0.2495240, 0.2994312, 0.3993490, 0.4993711, 0.5994664,
0.6996058, 0.7997553, 0.8998927, 0.9499514, 1.0000000, 0.0000000, 0.006114,
0.0062188, 0.0087532, 0.0138088, 0.0264052, 0.0515127, 0.0765762, 0.1016176,
0.1516652, 0.2016828, 0.2516733, 0.3016387, 0.4015163, 0.5013438, 0.6011363,
0.7008976, 0.8006328, 0.9003380, 0.9501740, 1.0000000]
y = [0.0000000, 0.0233088, 0.0298517, 0.0425630, 0.0603942, 0.0739301, 0.0850687,
0.1023515, 0.1149395, 0.1230325, 0.1272298, 0.1253360, 0.1130538, 0.0934796,
0.0695104, 0.0445423, 0.0207728, 0.0098870, 0.0000000, 0.0000000, -.0208973,
-.0210669, -.0247377, -.0307807, -.0416431, -.0548774, -.0637165, -.0703581,
-.0801452, -.0869356, -.0910290, -.0926252, -.0905235, -.0834273, -.0728351,
-.0591463, -.0428603, -.0235778, -.0122883, 0.0000000]
plt.plot(x,y)
這是我從網站上抓取的資料點。如果我繪制此圖，則有一條從 (0,0) 到 (1,0) 的線是我不想要的。我已經嘗試手動洗掉點并查看我需要洗掉哪些點，但我似乎無法讓它作業。該資料點中有兩對相同的點。如何洗掉從 (0,0) 到 (1,0) 的線，并且可以通過 usingif陳述句將其自動化？
uj5u.com熱心網友回復：
如果您仔細查看您的資料，似乎存在不連續性。你的 x 值開始上升，然后回到 0，然后再次上升。這種不連續性正在創建困擾您的水平線。您可以遍歷xand y，檢測何時x下降而不是增加的值，找到該索引并將兩個串列分開。但是，使用np.diff也可以幫助解決這個問題。在這種特定情況下，只有一滴，所以你只有一個負值diff。這是我的代碼和我得到的圖表。它可能不會推廣到任何數量的不連續性，但它可以解決您的問題。
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np
x = [0.0000000,0.0082707,0.0132000, 0.0255597, 0.0503554, 0.0751941, 0.1000570,
0.1498328, 0.1996558, 0.2495240, 0.2994312, 0.3993490, 0.4993711, 0.5994664,
0.6996058, 0.7997553, 0.8998927, 0.9499514, 1.0000000, 0.0000000, 0.006114,
0.0062188, 0.0087532, 0.0138088, 0.0264052, 0.0515127, 0.0765762, 0.1016176,
0.1516652, 0.2016828, 0.2516733, 0.3016387, 0.4015163, 0.5013438, 0.6011363,
0.7008976, 0.8006328, 0.9003380, 0.9501740, 1.0000000]
y = [0.0000000, 0.0233088, 0.0298517, 0.0425630, 0.0603942, 0.0739301, 0.0850687,
0.1023515, 0.1149395, 0.1230325, 0.1272298, 0.1253360, 0.1130538, 0.0934796,
0.0695104, 0.0445423, 0.0207728, 0.0098870, 0.0000000, 0.0000000, -.0208973,
-.0210669, -.0247377, -.0307807, -.0416431, -.0548774, -.0637165, -.0703581,
-.0801452, -.0869356, -.0910290, -.0926252, -.0905235, -.0834273, -.0728351,
-.0591463, -.0428603, -.0235778, -.0122883, 0.0000000]
discont = np.diff(x).argmin()
x1 = x[:discont 1]
y1 = y[:discont 1]
x2 = x[discont 1:]
y2 = y[discont 1:]
plt.plot(x1, y1)
plt.plot(x2, y2)
plt.show()
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標籤：matplotlib 自动化