我有一個帶有日期索引的df，如下所示：
ind = pd.date_range(start="2015-12-31", end = "2022-04-26", freq="D")
df = pd.DataFrame(
{
"col1": range(len(ind))
},
index=ind
)
我需要的是從 2017-08-31 到 3 年加 1 個月的每個月底將 windows 中的 df 切片，所以我有下一段代碼
n = timedelta(365 * 3) relativedelta(months=1)
fechas_ = pd.date_range("2017-08-31", ind.max() - n, freq="M")
# create a for loop to check the beginning and the end of each window
for i in fechas_:
print(f"start: {i}")
print(f"end: {i n}")
print("\n")
我的問題是我需要每月的最后一天作為每個視窗的結束，例如：
# first window
start: 2017-08-31 00:00:00
end: 2020-09-30 00:00:00
# second window
start: 2017-09-30 00:00:00
end: 2020-10-31 00:00:00
# so on
但我得到：
# first window
start: 2017-08-31 00:00:00
end: 2020-09-29 00:00:00
# second window
start: 2017-09-30 00:00:00
end: 2020-10-29 00:00:00
# 3
2017-10-31 00:00:00
2020-11-29 00:00:00
# 4
2017-11-30 00:00:00
2020-12-29 00:00:00
# 5
2017-12-31 00:00:00
2021-01-30 00:00:00
# 6
2018-01-31 00:00:00
2021-02-27 00:00:00
# 7
2018-02-28 00:00:00
2021-03-27 00:00:00
# 8
2018-03-31 00:00:00
2021-04-29 00:00:00
# 9
2018-04-30 00:00:00
2021-05-29 00:00:00
# 10
2018-05-31 00:00:00
2021-06-29 00:00:00
# 11
2018-06-30 00:00:00
2021-07-29 00:00:00
# 12
2018-07-31 00:00:00
2021-08-30 00:00:00
# 13
2018-08-31 00:00:00
2021-09-29 00:00:00
# 14
2018-09-30 00:00:00
2021-10-29 00:00:00
# 15
2018-10-31 00:00:00
2021-11-29 00:00:00
# 16
2018-11-30 00:00:00
2021-12-29 00:00:00
# 17
2018-12-31 00:00:00
2022-01-30 00:00:00
# 18
2019-01-31 00:00:00
2022-02-27 00:00:00
# 19
2019-02-28 00:00:00
2022-03-27 00:00:00
有人知道我該如何解決這個問題嗎？
非常感謝
uj5u.com熱心網友回復：
在您的代碼中
n = timedelta(365 * 3) relativedelta(months=1)
嘗試將其替換為
n = relativedelta(years=3, months=1, day=31)
轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/469403.html
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