請幫忙。我試圖確保用戶在重新加載頁面后不會注銷。
const signUp = async (loginEmail, loginPassword) => {
const auth = getAuth()
setPersistence(auth, browserSessionPersistence)
.then(({ user }) => {
dispatch(
setUser({
email: user.email,
id: user.uid,
token: user.accessToken,
})
)
return signInWithEmailAndPassword(auth, loginEmail, loginPassword)
})
.catch((error) => {
console.log(error.message)
})
}
這是官方檔案中的示例
const auth = getAuth();
setPersistence(auth, browserSessionPersistence)
.then(() => {
// Existing and future Auth states are now persisted in the current
// session only. Closing the window would clear any existing state even
// if a user forgets to sign out.
// ...
// New sign-in will be persisted with session persistence.
return signInWithEmailAndPassword(auth, email, password);
})
.catch((error) => {
// Handle Errors here.
const errorCode = error.code;
const errorMessage = error.message;
});
uj5u.com熱心網友回復：
獲取當前用戶的推薦方法是在 Auth 物件上設定觀察者：
import { getAuth, onAuthStateChanged } from "firebase/auth";
const auth = getAuth();
onAuthStateChanged(auth, (user) => {
if (user) {
// User is signed in, see docs for a list of available properties
// https://firebase.google.com/docs/reference/js/firebase.User
const uid = user.uid;
// ...
} else {
// User is signed out
// ...
}
});
檔案
轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/493587.html
標籤：javascript 火力基地 firebase 身份验证
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