我一直在搜索 itertools 的檔案以及 SO 一段時間，但還沒有找到我要找的東西。我希望反轉 for 回圈的執行順序，因此會發生以下情況：
for letter in ["A","B","C"]:
do_something(letter)
do_something_else(letter)
def do_something(letter):
print("do_something with " letter)
def do_something_else(letter):
print("do something_else with " letter)
for 回圈的正常輸出為：
do_something with A
do something_else with A
do_something with B
do something_else with B
do_something with C
do something_else with C
我希望它（迭代器）輸出如下：
do_something with A
do_something with B
do_something with C
do something_else with A
do something_else with B
do something_else with C
我不會說謊，這是漫長的一天，所以答案可能就在我的眼皮底下，到目前為止我想出的最好的答案是：
for letter in ["A","B","C"]:
do_something(letter)
for letter in ["A","B","C"]:
do_something_else(letter)
def do_something(letter):
print("do_something with " letter)
def do_something_else(letter):
print("do something_else with " letter)
但這感覺很笨拙，因為我在重復 for 回圈。非常感謝任何幫助。謝謝大家！
uj5u.com熱心網友回復：
進行兩次迭代：
for letter in ["A","B","C"]:
do_something(letter)
for letter in ["A","B","C"]:
do_something_else(letter)
uj5u.com熱心網友回復：
另一種選擇是對函式進行外回圈，對字母進行內回圈。
for f in [do_something, do_something_else]:
for letter in ["A","B","C"]:
f(letter)
然而，另一種選擇是在輸入函式上使用 itertools/product（輸出是所希望的）。
from itertools import product
for f, letter in product([do_something, do_something_else], ["A","B","C"]):
f(letter)
uj5u.com熱心網友回復：
怎么樣
results = [list(map(func,letters)) for func in [do_something,do_something_else]]
uj5u.com熱心網友回復：
您可以使用該itertools.tee()函式創建兩個獨立的字母迭代器，并使用內置zip()函式將函式和字母“編織”在一起，如下所示：
from itertools import tee
def do_something(letter):
print("do_something with " letter)
def do_something_else(letter):
print("do something_else with " letter)
for function, letters in zip((do_something, do_something_else), tee(["A","B","C"]) ):
for letter in letters:
function(letter)
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標籤：Python python-3.x for循环 迭代工具
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